< cpp‎ | memory‎ | allocator
pointer allocate( size_type n, std::allocator<void>::const_pointer hint = 0 );

Allocates n * sizeof(T) bytes of uninitialized storage by calling ::operator new(std::size_t), but it is unspecified when and how this function is called. The pointer hint may be used to provide locality of reference: the allocator, if supported by the implementation, will attempt to allocate the new memory block as close as possible to hint.


[edit] Parameters

n - the number of objects to allocate storage for
hint - pointer to a nearby memory location

[edit] Return value

Pointer to the first byte of a memory block suitably aligned and sufficient to hold an array of n objects of type T.

[edit] Exceptions

Throws std::bad_alloc if allocation fails.

[edit] See also

allocates uninitialized storage using the allocator
(public static member function of std::allocator_traits)